Do dhuine ar bith ar mhaith leo a rith a gcuid rothar leictreach uaire de toilleoirí in iúl dom a shábháil tú roinnt ama.
Freagra Simplí:
Le nach bhfuil toilleoirí teicneolaíochta reatha ina rogha inmharthana do thiomáint ar rothar leictreach.
Freagra Meánach:
Faoi láthair, Is é an dlús fuinnimh le haghaidh toilleoirí ultra ag fearr faoi 1/10 go na cadhnraí aigéad luaidhe mar sin bheadh sé a chur faoi 10 huaire an meáchan i toilleoirí ultra mar a bheadh sé do cadhnraí aigéad luaidhe. Mura bhfuil tú seomra do £ 300 de toilleoirí nach bhfuil sé seo i ndáiríre an rogha.
A gníomh vicí beag:
(35 W·h / kg i gcás ultracapacitor caighdeánach, cé go 85 W.h / kg curtha i gcrích i saotharlann mar na 2010 i gcomparáid le 30-40 I·h / kg i gcás mar thoradh ar ceallraí aigéad)
| Paraiméadair |
Capacitor leictreastatach |
Ultracapacitor |
Battery |
| Am Scaoilte |
10-6~ 10-3soic |
1~ 30 soic |
0.3~ 3 uair an chloig |
| Am Muirear |
10-6~ 10-3soic |
1~ 30 soic |
1~ 5 uair an chloig |
| Dlús Fuinnimh (WH / kg) |
< 0.1 |
1~ 10 |
20~ 100 |
| Dlús Power (W / kg) |
< 10,000 |
10,000 |
50~ 200 |
| Muirear / Éifeachtacht Urscaoileadh |
~ 1.0 |
~ 10 |
0.7~ 0.85 |
| Saol na Sraithe |
Infinite |
> 500,000 |
500~ 2,000 |
http://www.nesscap.com / táirge / overview.jsp
http://en.wikipedia.org / wiki / Energy_density
http://en.wikipedia.org / wiki / Ultracapacitor
Freagra Fada:
A cheangal ar Fiú thurais ghearra 4 nó 5 uair an chloig Dodgers de chumhacht ag an voltas rátáil a bheith éifeachtach.
Daoine eile a d'iarr ar an gceist chéanna ar fóraim idirlín il, agus ba é an freagra is fearr raibh mé in ann teacht ar an.
1 Farad é 1 Aimpéar in aghaidh an dara bholta. 1 F = 1 Mar a / V.
1 Ah = 3600 Mar a
3600 Mar a / 12V = 300 Mar a / V = 300F
Ach is gá duit níos mó ansin go mar go mbeidh an voltas titim mar an scardadh toilleoir. Ciallaíonn Leath an muirear leath an voltas.
Le ceallraí aigéad luaidhe go bhfuil éagsúla. A ceallraí go bhfuil leath folamh tá fós beagnach an voltas céanna mar a bhí sé ag tús.
Maybe 600F and some electronics to automatically step up the voltage so it stays at 12V.
So you’d need to buy 160 capacitors with 3V and 60F each.
http://www.physicsforums.com/showthread.php?t=256751
Even after reading the above statement I decided to do more research and see if there is any new technology that could be useful. Ultra capacitors are starting to come down in price and are readily available, but they still are not cheap.
It is possible buy capacitors that are rated for 3000F and 2.7 volts, and their data sheets state that they have 3.30 Wh (~1.2Ah = 3.3Wh / 2.7V) of usable stored energy. The problem is that the calculation does not factor in the voltage drop that takes place as the capacitor discharges.
Ideally, with a bike you would want to run somewhere between 60 agus 36 volts for a hub motor.
There are two options:
1. A voltage multiplier circuit.
2. A string of ultra capacitors in series.
The first idea is probably the better one, but it is fairly technical and goes beyond the scope of a blog post.
The basic math behind a series string of capacitors would be this. (Capacitance drops as capacitors are added in series.) 1/((1/3000)+(1/3000)+(1/3000)+(1/3000)+(1/3000)+(1/3000)+(1/3000)+(1/3000)+(1/3000)+(1/3000)+(1/3000)+(1/3000)+(1/3000)+(1/3000)+(1/3000)+(1/3000)+(1/3000)+(1/3000)) ; 166. 7F
Theoretical storage would be
166. 7F*48V = 8000As
8000As/ 3600 As = 2.2 Ah
Mar sin féin, the usable potential is likely 1.2Ah which is stated on the data sheet, and the hub motor will operate most effectively between 48 agus 36 volts. That is a 12V change and happens to provide access to about 25% of the usable 1.2 Ah in a simple series circuit.
……………………………. This is getting too boring.
If you still want to know more about sizing ultra capacitors for electric vehicles this article provides the required calculations. http://people.clarkson.edu/~pillayp/c1.pdf
Conclusion:
Start considering ultra capacitors for application in electric bikes when ratings of 12000F + capacitors become available. There were a lot of claims in 2007 agus 2008 that we would see the end of batteries, but it looks like someone is getting close.
http://physicsworld.com/cws/article/news/44477
